Ruby on Rails：表关系搜索
我仍然无法搜索存储在单独表中的技术，其中技术表（technol）和Project表之间通过名为projecttechnol的表之间存在关系。
当我尝试使用技术（tech1）搜索项目时，这是我的日志。
Parameters: {"utf8"=>"✓", "client"=>"", "industry"=>"", "role"=>"", "technols"=>{"id"=>["", "1", ""]}, "business_div"=>"", "project_owner"=>"", "start_date_dd"=>"", "start_date_A"=>"", "start_date_B"=>"", "status"=>"", "keywords"=>"", "per_page"=>"10"} User Load (0.6ms) SELECT "users".* FROM "users" WHERE "users"."id" = 1 LIMIT 1 Technol Load (0.3ms) SELECT "technols".* FROM "technols" Project Load (0.5ms) SELECT "projects".* FROM "projects" ORDER BY client Project Load (0.6ms) SELECT "projects".* FROM "projects" ORDER BY industry Project Load (0.4ms) SELECT "projects".* FROM "projects" ORDER BY role Project Load (0.4ms) SELECT "projects".* FROM "projects" ORDER BY tech CACHE (0.0ms) SELECT "projects".* FROM "projects" ORDER BY tech CACHE (0.0ms) SELECT "projects".* FROM "projects" ORDER BY tech CACHE (0.0ms) SELECT "projects".* FROM "projects" ORDER BY tech CACHE (0.0ms) SELECT "projects".* FROM "projects" ORDER BY tech CACHE (0.0ms) SELECT "projects".* FROM "projects" ORDER BY tech Project Load (0.6ms) SELECT "projects".* FROM "projects" ORDER BY business_div Project Load (0.5ms) SELECT "projects".* FROM "projects" ORDER BY project_owner Project Load (0.7ms) SELECT "projects".* FROM "projects" ORDER BY status (0.9ms) SELECT COUNT(*) FROM "projects" INNER JOIN "projecttechnols" ON "projecttechnols"."project_id" = "projects"."id" INNER JOIN "technols" ON "technols"."id" = "projecttechnols"."technol_id" WHERE "technols"."id" IS NULL 这是我的project.rb：
class Project :projecttechnols def self.like(text); "%#{text}%"; end def self.search(search_client, search_industry, search_role, search_tech_id, search_business_div, search_project_owner, search_status, search_start_date_dd, search_start_date_A, search_start_date_B, search_keywords) # start with a scoped query, to apply more scopes on it afterwards _projects = Project.scoped # then, for each of the parameters, apply the scope only if present if search_client.present? _projects = _projects.where ['client LIKE ?', like(search_client)] end if search_industry.present? _projects = _projects.where ['industry LIKE ?', like(search_industry)] end if search_role.present? _projects = _projects.where ['role LIKE ?', like(search_role)] end _projects = _projects.joins(:technols). where("technols.id" => search_techs_ids) if search_business_div.present? _projects = _projects.where ['business_div LIKE ?', like(search_business_div)] end if search_project_owner.present? _projects = _projects.where ['project_owner LIKE ?', like(search_project_owner)] end if search_status.present? _projects = _projects.where ['status LIKE ?', like(search_status)] end todays_date = DateTime.now.to_date if !search_start_date_A.blank? or !search_start_date_B.blank? search_start_date_A = Date.parse(search_start_date_A).strftime("%Y-%m-%d") search_start_date_B = Date.parse(search_start_date_B).strftime("%Y-%m-%d") todays_date = nil search_start_date_dd = nil end if search_start_date_dd.blank? todays_date = nil end if search_start_date_A.present? or search_start_date_B.present? _projects = _projects.where [' DATE(start_date) BETWEEN ? AND ?', search_start_date_A, search_start_date_B] end if search_start_date_dd.present? _projects = _projects.where ['DATE(start_date) BETWEEN ? AND ?', search_start_date_dd, todays_date] end if search_keywords.present? _projects = _projects.where ['keywords LIKE ?', like(search_keywords)] end # now you have applied only the present scopes. return the result, and watch # the query as it executes. _projects end def self.paginated_for_index(projects_per_page, current_page) paginate(:per_page => projects_per_page, :page => current_page) end end
Technol.rb：
class Technol :projecttechnols end
Projecttechnol.rb
class Projecttechnol < ActiveRecord::Base attr_accessible :project_id, :technol_id belongs_to :technol belongs_to :project end
谁能正确地看到这项工作的解决方案。 我是rails的新手，所以在试图帮助我时请记住这一点。 在技术领域中搜索任何内容都不会返回任何内容。 非常感谢
看起来你的搜索参数中有拼写错误：
def self.search(search_client, search_industry, search_role, search_tech_id...
但是你在这里使用search_techs_id ：
_projects = _projects.joins(:technols).where("technols.id" => search_techs_ids)
如果检查查询，可以看到它尝试使用NULL连接两个表。
另外请注意，您的搜索查询有点长且难以阅读，我建议您使用以下内容：
class Project < ActiveRecord::Base attr_accessible :edited_first_name, :edited_last_name, :first_name, :last_name, :business_div, :client, :customer_benifits, :edited_date, :end_date, :entry_date, :financials, :industry, :keywords, :lessons_learned, :project_name, :project_owner, :role, :start_date, :status, :summary, :tech_id validates_presence_of :business_div, :client, :customer_benifits, :end_date, :financials, :industry, :keywords, :lessons_learned, :project_name, :project_owner, :role, :start_date, :status, :summary#, :tech has_many :projecttechnols has_many :technols, :through => :projecttechnols scope :client, { |client| where ['client LIKE ?', like(client) ] } scope :industry, { |industry| where ['industry LIKE ?', like(industry)] } scope :role, { |role| where ['role LIKE ?', like(search_role)] } scope :technologies, { |technology_ids| joins(:technols).where("technols.id}" => technology_ids) } scope :division, { |division| where ['business_div LIKE ?', like(search_business_div)] } scope :owner, { |owner| where ['project_owner LIKE ?', like(search_project_owner)] } scope :status, { |status| where ['status LIKE ?', like(search_status)] } scope :keywords, { |keywords| where ['keywords LIKE ?', like(keywords)] } scope :started_before, { |date| where ['start_date <= ?',date] } scope :started_after, { |date| where ['start_date >= ?',date] } def self.search_fields [:client,:industry,:role,:technologies,:division,:owner,:status,:started_before,:started_after,:keywords] end def self.search(params) search_fields.inject(scoped) do |scopes,key| params[key].present? ? scopes.send(key,params[key]) : scopes end end def self.like(text); "%#{text}%"; end def self.paginated_for_index(projects_per_page, current_page) paginate(:per_page => projects_per_page, :page => current_page) end end
这样，您的搜索方法就会缩短，因为您已将所有这些参数分解到自己的作用域中，如果需要重用它们，方法已经存在。
希望这可以帮助。
我想在控制器中你可以从表单中获得正确的值。
这是你的params ：
{"utf8"=>"✓", "client"=>"", "industry"=>"", "role"=>"", "technols"=>{"id"=>["", "1", ""]}, "business_div"=>"", "project_owner"=>"", "start_date_dd"=>"", "start_date_A"=>"", "start_date_B"=>"", "status"=>"", "keywords"=>"", "per_page"=>"10"}
因此所选技术ID的列表是params["technols"]["id"] ，即["", "1", ""] 。 如果是这样，那么你必须删除它的空白
tech_ids = params["technols"]["id"].reject(&:blank?) # removes empty strings
并在搜索function中传递它。 如果它不是预期的，那么检查用于创建选择框的代码，因为它必须返回正确的ID