Ruby gsub字符串中的多个字符
使用Ruby 1.9.3,Rails 3.2,我有以下内容:
"every good boy does fine".gsub("every", "all").gsub("boy", "girl").gsub("fine", "well") # => "all good girl does well"
有没有更好的方法来写这个? 谢谢。
String#gsub
和Hash#fetch
将是这个的好选择。
a = "every good boy does fine" h = {"every" => "all","boy" => "girl", "fine" =>"well" } a.gsub(/\w+/) { |m| h.fetch(m,m)} # => "all good girl does well"
要么,
a = "every good boy does fine" h = {"every" => "all","boy" => "girl", "fine" =>"well" } Regexp.new("^#{h.keys.join('|')}$") # => /^every|boy|fine$/ a.gsub(Regexp.new("^#{h.keys.join('|')}$"),h) # => "all good girl does well"
replacements = [ ["every", "all"], ["boy", "girl"],["fine", "well"] replacements.each {|replacement| str.gsub!(replacement[0], replacement[1])}
我不知道它是否更好,但更清洁。
subs = { "every" => "all", "boy" => "girl", "fine" => "well" } "every good boy does fine".gsub(/\w+/) { |m| subs[m] || m } # => 'all good girl does well'
如果目的是避免方法链接:
[9] pry(main)> "every good boy does fine".gsub("every", "all").gsub("boy", "girl").gsub("fine", "well") => "all good girl does well" [10] pry(main)> "every good boy does fine".gsub(/(every)|(boy)|(fine)/) do |word| [10] pry(main)* case word [10] pry(main)* when "every" [10] pry(main)* "all" [10] pry(main)* when "boy" [10] pry(main)* "girl" [10] pry(main)* when "fine" [10] pry(main)* "well" [10] pry(main)* end [10] pry(main)* end => "all good girl does well"
或者:
[11] pry(main)> REPLACEMENT = { "every" => "all", "boy" => "girl", "fine" => "well"} => {"every"=>"all", "boy"=>"girl", "fine"=>"well"} [12] pry(main)> "every good boy does fine".gsub(/(every)|(boy)|(fine)/) { |word| REPLACEMENT[word] } => "all good girl does well"
这样做:
“每个好男孩都做得很好”.gsub(/ \ w + /,’every’=>’all’,’boy’=>’girl’,’fine’=>’well’)
更容易阅读:)这个简单的问题的一些答案真的让我想知道…哈哈
这里是参考: http : //ruby-doc.org/core-2.1.4/String.html
GG