使用Ransack对父级父级的属性进行排序
我知道如何使用Ransack对于父属性的令人敬畏的sort_link方法，但是当我将相同的逻辑外推到祖父母的属性时，它不起作用（我可以点击链接，不进行排序）。
层次结构如下： Signup has_many Request has_many Transaction 。 我正在从Transaction透视图中搜索。
控制器代码：
def index @q = Transaction.ransack(params[:q]) @transactions = @q.result.includes(:request => :signup) end
查看代码：
顺便提一下，搜索代码（例如:request_returndate_eq ）很好，它只是排序不起作用。
型号代码：
class Signup < ActiveRecord::Base has_many :requests end class Request < ActiveRecord::Base belongs_to :signup has_many :transactions, dependent: :destroy end class Transaction < ActiveRecord::Base belongs_to :request end
控制台输出
在第一次单击以升序排序（尽管任何单击它总是产生200响应，即使视图实际上没有更改）
Started GET "/admin/transactions?q%5Bs%5D=requests.signups.email+asc" for 127.0.0.1 at 2014-07-07 13:40:16 -0700 Processing by TransactionsController#index as HTML Parameters: {"q"=>{"s"=>"requests.signups.email asc"}} Rendered layouts/_flash.html.erb (0.6ms) (0.4ms) SELECT "transactions"."name" FROM "transactions" Transaction Load (0.6ms) SELECT "transactions".* FROM "transactions" Request Load (0.3ms) SELECT "requests".* FROM "requests" WHERE "requests"."id" IN (11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50) Signup Load (0.1ms) SELECT "signups".* FROM "signups" WHERE "signups"."id" IN (4, 5, 1, 2) Rendered transactions/index.html.erb within layouts/application (74.3ms) Completed 200 OK in 85ms (Views: 81.7ms | ActiveRecord: 1.4ms)
您可以使用委托来避免视图中的父表达式或父表达式。
模型
class Transaction < ActiveRecord::Base belongs_to :request delegate :email, to: :request, prefix: true end
交易查看代码：
<%= sort_link(@q, 'request_email', "Email") %>