将字符串拆分为指定大小的块,而不会破坏单词

我需要根据特定大小将字符串拆分为块。 我不能打破块之间的单词,所以我需要抓住当添加下一个单词将超过块大小并启动​​下一个单词时(如果块小于指定大小则可以)。

这是我的工作代码,但我想找到一种更优雅的方式来做到这一点。

def split_into_chunks_by_size(chunk_size, string) string_split_into_chunks = [""] string.split(" ").each do |word| if (string_split_into_chunks[-1].length + 1 + word.length > chunk_size) string_split_into_chunks << word else string_split_into_chunks[-1] << " " + word end end return string_split_into_chunks end 

怎么样:

 str = "split a string into chunks according to a specific size. Seems easy enough, but here is the catch: I cannot be breaking words between chunks, so I need to catch when adding the next word will go over chunk size and start the next one (its ok if a chunk is less than specified size)." str.scan(/.{1,25}\W/) => ["split a string into ", "chunks according to a ", "specific size. Seems easy ", "enough, but here is the ", "catch: I cannot be ", "breaking words between ", "chunks, so I need to ", "catch when adding the ", "next word will go over ", "chunk size and start the ", "next one (its ok if a ", "chunk is less than ", "specified size)."] 

@sawa评论后更新:

 str.scan(/.{1,25}\b|.{1,25}/).map(&:strip) 

这样更好,因为它不需要字符串以\ W结尾

它将处理超过指定长度的单词。 实际上它会分裂它们,但我认为这是理想的行为

@Yuriy,你的轮换看起来很麻烦。 怎么样:

 str.scan /\S.{1,24}(?!\S)/ #=> ["split a string into", "chunks according to a", "specific size. Seems easy", "enough, but here is the", "catch: I cannot be", "breaking words between", "chunks, so I need to", "catch when adding the", "next word will go over", "chunk size and Start the", "next one (its ok if a", "chunk is less than", "specified size)."]