从Ruby中的哈希数组中删除哈希
我有一系列哈希如下：
[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}] 现在，我想首先检查数组是否包含带有值为"v3"键"k1"的散列。 如果是，那么我想从数组中删除该哈希。
结果应该是：
[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]
使用Array#delete_if ：
arr = [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}] arr.delete_if { |h| h["k1"] == "v3" } #=> [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]
如果没有匹配条件的哈希，则数组保持不变。
您可以使用Array#reject （如果您不想修改接收器）以及Array#reject! （如果要修改接收器）
arr = [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}] p arr.reject { |h| h["k1"] == "v3" } # >> [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}] arr = [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}] p arr.reject! { |h| h["k1"] == "v3" } # >> [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]