内置的方式列出ruby目录中的目录

有没有更清洁的内置方式来做到这一点？

ree> Pathname.new('/path/to').children.select{|e| e.directory?}.map{|d| d.basename.to_s} => ["test1", "test2"] 

理想情况下我想避开该directory? 呼叫

Answer 1

从Chandra的答案开始，根据您是否需要完整路径，您可以使用

 Dir['app/*/'] # => ["app/controllers/", "app/helpers/", "app/metal/", "app/models/", "app/sweepers/", "app/views/" Dir['app/*/'].map { |a| File.basename(a) } # => ["controllers", "helpers", "metal", "models", "sweepers", "views"] 

如果使用Ruby> = 1.8.7，Chandra的答案也可以改写为

 Pathname.glob('app/*/').map(&:basename) # you can skip .to_s unless you don't need to work with strings # remember you can always use a pathname as string for the most part of Ruby functions # or interpolate the value 

Answer 2

 Pathname.glob("/path/to/*/").map { |i| i.basename.to_s }