Ruby嵌套每个do +数组连接

*新手道歉..

以下代码：

dates = ['Transaction_Date','Renewal_Date'] dateoptions = ['Year','Month','Date'] word1 = "Amount" dates.each do |x| puts word1 + " by " + x end 

返回

 Amount by Transaction_Date Amount by Renewal_Date 

我希望结果是日期和日期选项的串联，就像这样

 Amount by Transaction_Date (Year) Amount by Transaction_Date (Month) Amount by Transaction_Date (Date) Amount by Renewal_Date (Year) Amount by Renewal_Date (Month) Amount by Renewal_Date (Month) 

我正在考虑做一个嵌套的“每个做”但我仍然不知道如何解决两个数组的连接。

感谢您的意见

Answer 1

您需要使用嵌套的each ：

 dates = ['Transaction_Date','Renewal_Date'] dateoptions = ['Year','Month','Date'] word1 = "Amount" dates.each do |d| dateoptions.each do |option| puts "#{word1} by #{d} (#{option})" end end 

或者您可以使用Array#product

 dates.product(dateoptions) do |d, option| puts "#{word1} by #{d} (#{option})" end 

Answer 2

您可以使用Array#product方法：

 dates.product(dateoptions).each do |date, option| puts "#{word1} by #{date} (#{option})" end 

Answer 3

 dates = ['Transaction_Date','Renewal_Date'] dateoptions = ['Year','Month','Date'] word1 = "Amount" dates.each do |x| dateoptions.each do |y| puts "#{word1} by #{x} (#{y})" end end 

Answer 4

 2.1.2 :009 > dates.each do |e| 2.1.2 :010 > dateoptions.each do |o| 2.1.2 :011 > puts "#{word1} by #{e} (#{o})" 2.1.2 :012?> end 2.1.2 :013?> end Amount by Transaction_Date (Year) Amount by Transaction_Date (Month) Amount by Transaction_Date (Date) Amount by Renewal_Date (Year) Amount by Renewal_Date (Month) Amount by Renewal_Date (Date)