使用Ruby中的变量重命名文件
如何使用变量重命名Ruby中的文件?
File.rename("text1.txt", "text2.txt")
上面的例子在使用irb时很好,但是我编写了一个脚本,其中var1和var2都不为我所知。
例如:
script_dir = File.expand_path File.dirname(__FILE__) Dir.chdir(script_dir) Dir.glob('Cancer1-1.pencast').each do |pencast| pencast_title = File.basename(File.basename(pencast), '.*') i = 1 audio_title = File.basename(`unzip -l #{pencast} | grep .aac | awk '{print $4;}' | awk 'NR=='#{i}''`) audio_path = `unzip -l #{pencast} | grep .aac | awk '{print $4;}' | awk 'NR=='#{i}''` audio_extension = File.extname(File.basename(audio_path)) new_name = "#{pencast_title}-#{i}#{audio_extension}" File.rename(audio_title, new_name)
不起作用……但如果我使用puts var1
我会看到我想要的文件名。
我得到的错误是:
prog_test.rb:12:in `rename': No such file or directory - audio-0.aac (Errno::ENOENT) or Cancer1-1-1.aac from prog_test.rb:12 from prog_test.rb:5:in `each' from prog_test.rb:5
但文件audio-0.aac
在那里……我在看它。
我确定我找到了问题:它似乎是在另一个变量中添加一个变量。 这是一个产生相同输出的简化示例:
audio_title = "audio-0.aac" fullPath = File::SEPARATOR + "Users" + File::SEPARATOR + "name" + File::SEPARATOR + "Desktop" + File::SEPARATOR + audio_title newname = File::SEPARATOR + "Users" + File::SEPARATOR + "name" + File::SEPARATOR + "Desktop" + File::SEPARATOR + "audio1.aac" puts fullPath puts newname File.rename(fullPath, newname)
输出:
/Users/name/Desktop/audio-0.aac /Users/name/Desktop/audio1.aac prog_test.rb:22:in `rename': No such file or directory - /Users/name/Desktop/audio-0.aac or /Users/name/Desktop/audio1.aac (Errno::ENOENT) from prog_test.rb:22
您应该将完整的文件路径传递给File.rename
,而不仅仅是basename
我不确定File.basename()
中的示例中发生了什么,但想象如下:
fullPath = "C:" + File::SEPARATOR + "Folder" + File::SEPARATOR + "File.txt" # C:\Folder\File.txt basename = File.basename(fullPath) # File newFileName = "File.bak" File.rename(basename, newFileName) # How can Ruby possibly know which directory to find the above file in, or where to put it? - It will just look in the current working directory
因此,您需要将完整路径传递给File.rename,如下所示:
fullPath = "C:" + File::SEPARATOR + "Folder" + File::SEPARATOR + "File.txt" # C:\Folder\File.txt directory = File.dirname(fullPath) # C:\Folder newFileName = "File.bak" File.rename(fullPath, directory + File::SEPARATOR + newFileName)