Heroku加入/包括不像sqlite开发环境那样工作
所以这就是我在我的开发（SQLite）环境中完美运行的东西：
key = "%#{keywords}%" listings = Listing.order(:headline) listings = listings.includes(:neighborhood).where("headline like ? or neighborhoods.name like ?", key, key) if keywords.present? 但是，当我在Heroku上尝试类似的东西时，我会遇到一些错误：
listings = listings.includes(:neighborhood).where("headline like ? or neighborhoods.name like ?", key, key) ActiveRecord::ConfigurationError: Association named 'neighborhoods' was not found; perhaps you misspelled it?
我也尝试了以下内容并得到了相应的错误：
> listings = Listing.includes(:neighborhood).where("headline like :keywords or neighborhood.name like :keywords", :keywords => "%#{keywords}%") SQL (3.1ms) SELECT "listings"."id" AS t0_r0, "listings"."listing_category_id" AS t0_r1, "listings"."listing_type_id" AS t0_r2, "listings"."user_id" AS t0_r3, "listings"."boro_id" AS t0_r4, "listings"."neighborhood_id" AS t0_r5, "listings"."building_id" AS t0_r6, "listings"."term_id" AS t0_r7, "listings"."headline" AS t0_r8, "listings"."property_type_id" AS t0_r9, "listings"."unit_num" AS t0_r10, "listings"."common_charges" AS t0_r11, "listings"."taxes" AS t0_r12, "listings"."maintenance" AS t0_r13, "listings"."num_bedrooms" AS t0_r14, "listings"."num_bathrooms" AS t0_r15, "listings"."square_footage" AS t0_r16, "listings"."list_square_footage" AS t0_r17, "listings"."description" AS t0_r18, "listings"."condition_id" AS t0_r19, "listings"."pet_policy_id" AS t0_r20, "listings"."exposure_id" AS t0_r21, "listings"."floor_plan" AS t0_r22, "listings"."photo" AS t0_r23, "listings"."security" AS t0_r24, "listings"."coop_deductible" AS t0_r25, "listings"."flip_tax" AS t0_r26, "listings"."house_families" AS t0_r27, "listings"."house_extensions" AS t0_r28, "listings"."house_stories" AS t0_r29, "listings"."house_units" AS t0_r30, "listings"."created_at" AS t0_r31, "listings"."updated_at" AS t0_r32, "listings"."price" AS t0_r33, "neighborhoods"."id" AS t1_r0, "neighborhoods"."name" AS t1_r1, "neighborhoods"."created_at" AS t1_r2, "neighborhoods"."updated_at" AS t1_r3, "neighborhoods"."boro_id" AS t1_r4 FROM "listings" LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%') ActiveRecord::StatementInvalid: PG::Error: ERROR: missing FROM-clause entry for table "neighborhood" LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho... ^ : SELECT "listings"."id" AS t0_r0, "listings"."listing_category_id" AS t0_r1, "listings"."listing_type_id" AS t0_r2, "listings"."user_id" AS t0_r3, "listings"."boro_id" AS t0_r4, "listings"."neighborhood_id" AS t0_r5, "listings"."building_id" AS t0_r6, "listings"."term_id" AS t0_r7, "listings"."headline" AS t0_r8, "listings"."property_type_id" AS t0_r9, "listings"."unit_num" AS t0_r10, "listings"."common_charges" AS t0_r11, "listings"."taxes" AS t0_r12, "listings"."maintenance" AS t0_r13, "listings"."num_bedrooms" AS t0_r14, "listings"."num_bathrooms" AS t0_r15, "listings"."square_footage" AS t0_r16, "listings"."list_square_footage" AS t0_r17, "listings"."description" AS t0_r18, "listings"."condition_id" AS t0_r19, "listings"."pet_policy_id" AS t0_r20, "listings"."exposure_id" AS t0_r21, "listings"."floor_plan" AS t0_r22, "listings"."photo" AS t0_r23, "listings"."security" AS t0_r24, "listings"."coop_deductible" AS t0_r25, "listings"."flip_tax" AS t0_r26, "listings"."house_families" AS t0_r27, "listings"."house_extensions" AS t0_r28, "listings"."house_stories" AS t0_r29, "listings"."house_units" AS t0_r30, "listings"."created_at" AS t0_r31, "listings"."updated_at" AS t0_r32, "listings"."price" AS t0_r33, "neighborhoods"."id" AS t1_r0, "neighborhoods"."name" AS t1_r1, "neighborhoods"."created_at" AS t1_r2, "neighborhoods"."updated_at" AS t1_r3, "neighborhoods"."boro_id" AS t1_r4 FROM "listings" LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
我也试过并得到以下错误：
0> listings = Listing.joins(:neighborhood).where("headline like :keywords or neighborhood.name like :keywords", :keywords => "%#{keywords}%") Listing Load (2.7ms) SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%') ActiveRecord::StatementInvalid: PG::Error: ERROR: missing FROM-clause entry for table "neighborhood" LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho... ^ : SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
思考？
谢谢。
编辑1：
列表belongs_to neighborhood ，邻居has_many listings 。
编辑2：
提取了一个SQL语句并通过psql ，结果如下：
SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%'); ERROR: missing FROM-clause entry for table "neighborhood" LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho...
试试以下内容：
listings = Listing.includes(:neighborhood).where("listings.headline like :keywords or neighborhoods.name like :keywords", :keywords => "%#{keywords}%")
我认为它应该调用listings.headline而不是headline
SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE ( headline like '%prospect heights%' #I mean here or neighborhood.name like '%prospect heights%') #also here, should be neighborhoods.name
编辑 – 你知道SQLite和PostgreSQL之间有什么区别吗？ 我遇到了类似的问题 。 我想你想要ILIKE而不是LIKE：
listings = Listing.includes(:neighborhood).where("listings.headline ilike :keywords or neighborhoods.name ilike :keywords", :keywords => "%#{keywords}%")
重新格式化的查询：
SELECT "listings"."id" AS t0_r0, "listings"."listing_category_id" AS t0_r1, "listings"."listing_type_id" AS t0_r2, "listings"."user_id" AS t0_r3, "listings"."boro_id" AS t0_r4, "listings"."neighborhood_id" AS t0_r5, "listings"."building_id" AS t0_r6, "listings"."term_id" AS t0_r7, "listings"."headline" AS t0_r8, "listings"."property_type_id" AS t0_r9, "listings"."unit_num" AS t0_r10, "listings"."common_charges" AS t0_r11, "listings"."taxes" AS t0_r12, "listings"."maintenance" AS t0_r13, "listings"."num_bedrooms" AS t0_r14, "listings"."num_bathrooms" AS t0_r15, "listings"."square_footage" AS t0_r16, "listings"."list_square_footage" AS t0_r17, "listings"."description" AS t0_r18, "listings"."condition_id" AS t0_r19, "listings"."pet_policy_id" AS t0_r20, "listings"."exposure_id" AS t0_r21, "listings"."floor_plan" AS t0_r22, "listings"."photo" AS t0_r23, "listings"."security" AS t0_r24, "listings"."coop_deductible" AS t0_r25, "listings"."flip_tax" AS t0_r26, "listings"."house_families" AS t0_r27, "listings"."house_extensions" AS t0_r28, "listings"."house_stories" AS t0_r29, "listings"."house_units" AS t0_r30, "listings"."created_at" AS t0_r31, "listings"."updated_at" AS t0_r32, "listings"."price" AS t0_r33, "neighborhoods"."id" AS t1_r0, "neighborhoods"."name" AS t1_r1, "neighborhoods"."created_at" AS t1_r2, "neighborhoods"."updated_at" AS t1_r3, "neighborhoods"."boro_id" AS t1_r4 FROM "listings" LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline LIKE '%prospect heights%' OR neighborhood.name LIKE '%prospect heights%');
问题似乎很明显。 你包括表“邻居”，但后来试图使用“邻居”。 如何在RoR中解决这个问题 – 不知道，但也许足以让你指出正确的方向。
诊断这一点的最佳方法是确保您的开发和生产环境尽可能匹配，并实际在本地运行PostgreSQL。 不可避免地，您会遇到难以调试的SQLite和PostgreSQL之间的不一致，或者在您推送代码时会让您感到惊讶。
如果你在Mac上，Heroku Postgres有一个独立的应用程序，你可以下载和使用，无需配置： http ： //postgresapp.com/