如何迭代天

我有一个用于循环days.this的代码来制作树叶。 我希望列登录和注销将在startdate自动开始并在enddate结束。

exp I input : startdate: 2012-11-08 01:30:00 enddate: 2012-11-10 01:30:00 i want output like this: 2012-11-08 01:30:00 2012-11-09 01:30:00 2012-11-010 01:30:00 for i in 0..((@leafe.enddate - @leafe.startdate).to_i) @attendance = Attendance.new @attendance.signin = '2012-11-08 01:30:00' #value must chang automatically @attendance.signout = '2012-11-08 10:30:00'#value must chang automatically @attendance.user_id = @leafe.user_id @attendance.save end 

谢谢你

Answer 1

如果startdate是Date类型，为什么不这样做，

 @attendance.signin = @leafe.startdate+i @attendance.signout = @leafe.startdate+i 

Answer 2

为什么你使用for循环？ 它看起来像javacode。 使用以下范围代替块：

 (Time.now.beginning_of_day.to_i..Time.now.to_i).step(3600) do |n|#step one hour for example @attendance = Attendance.new ....... @attendance.signin = @leafe.startdate @attendance.signout = @leafe.startdate + n # u can change time interval to any what you want end