使用Regex表达式搜索Ruby数组

嗨我有小ruby函数，拆分Ruby数组如下： –

def rearrange arr,from,to sidx = arr.index from eidx = arr.index to arr[sidx] = arr[sidx+1..eidx] end arr= ["Red", "Green", "Blue", "Yellow", "Cyan", "Magenta", "Orange", "Purple", "Pink", "White", "Black"] start = "Yellow" stop = "Orange" rearrange arr,start,stop puts arr.inspect #=> ["Red", "Green", "Blue", ["Cyan", "Magenta", "Orange"], "Cyan", "Magenta", "Orange", "Purple", "Pink", "White", "Black"] 

我需要在我的开始使用正则表达式并停止搜索，例如

开始=“/大喊/”

停止=“/ Ora /”

有没有一种简单的方法在Ruby中做到这一点？

Answer 1

当然，方法index可以接收一个块，这样就可以了

 sidx = arr.index{|e| e =~ from } 

您甚至可以查看Ruby的’case equality’运算符，并轻松地将字符串和正则表达式作为参数覆盖：

 sidx = arr.index{|e| from === e} # watch out: this is not the same as 'e === from' 

然后，如果你传递一个正则表达式，它将执行正则表达式匹配，如果你传递一个String ，它将寻找精确的字符串。