使用Rails保存之前将字符串转换为日期

对Ruby很新,我已经被困了几个小时。 到处搜索,找不到答案。

所以我正在使用rails gem的bootstrap datepicker。

因为我已经更改了日期选择器的日期格式,所以它不会存储在数据库中。 猜测这是因为simple_form输入被用作字符串以避免simple_form应用的默认日期选择输入。

我的问题是:如何将“06/18/2013”​​之类的字符串修改/转换为保存到数据库之前的日期? 这最好由控制器处理吗?

我的控制器:

# PUT /events/1 # PUT /events/1.json def update @event = Event.find(params[:id]) # Ugghhhh I need help # @event.event_date = Date.parse(params[:event_date]).to_date respond_to do |format| if @event.update_attributes(params[:event]) format.html { redirect_to @event, :notice => 'Event was successfully updated.' } format.json { head :no_content } else format.html { render :action => "edit" } format.json { render :json => @event.errors, :status => :unprocessable_entity } end end end 

数据库架构:

  create_table "events", :force => true do |t| t.string "event_name" t.string "event_location" t.date "event_date" t.time "event_time" t.text "event_content" t.datetime "created_at", :null => false t.datetime "updated_at", :null => false t.integer "user_id" t.boolean "approved", :default => true t.integer "category_id" end 

这是服务器日志:

  Started PUT "/events/1" for 127.0.0.1 at 2013-06-14 02:37:15 -0700 Processing by EventsController#update as HTML Parameters: {"utf8"=>"✓", "authenticity_token"=>"RYMdJ0lFmvG0+nVIsTtJXu5fyD/L3/WAKsk9FX6WWgo=", "event"=>{"user_id"=>"1", "category_id"=>"3", "event_name"=>"A Event Name", "event_location"=>"Event Location", "event_date"=>"06/13/2013", "event_time(1i)"=>"2000", "event_time(2i)"=>"1", "event_time(3i)"=>"1", "event_time(4i)"=>"02", "event_time(5i)"=>"18", "event_content"=>"First night"}, "commit"=>"Update Event", "id"=>"1"} User Load (0.2ms) SELECT "users".* FROM "users" WHERE "users"."id" = 1 LIMIT 1 Event Load (0.1ms) SELECT "events".* FROM "events" WHERE "events"."id" = ? LIMIT 1 [["id", "1"]] (0.0ms) begin transaction (0.0ms) commit transaction Redirected to http://localhost:3000/events/1 Completed 302 Found in 4ms (ActiveRecord: 0.3ms) 

您可以在控制器中使用strptime。

 DateTime.strptime("06/18/2013", "%m/%d/%Y") 

应该是正确的

DateTime.strptime(“02/06/2014”,“%d /%m /%Y”)。strftime(“%Y-%m-%d”)