Ruby数组一次访问2个连续（链接）元素

现在，这是arrays，

[1,2,3,4,5,6,7,8,9] 

我想要，

 [1,2],[2,3],[3,4] upto [8,9] 

当我这样做时，每个我都得到了（2），

 [[1,2],[3,4]..[8,9]] 

我目前这样做，

 arr.each_with_index do |i,j| p [i,arr[j+1]].compact #During your arr.size is a odd number, remove nil. end 

有没有更好的办法？？

Answer 1

Ruby读你的想法。 你想要连续元素吗？

 [1, 2, 3, 4, 5, 6, 7, 8, 9].each_cons(2).to_a # => [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]] 

Answer 2

.each_cons完全符合你的要求。

 [1] pry(main)> a = [1,2,3,4,5,6,7,8,9] => [1, 2, 3, 4, 5, 6, 7, 8, 9] [2] pry(main)> a.each_cons(2).to_a => [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]] 

Answer 3

你几乎做对了:)

 arr = [1,2,3,4,5,6,7,8,9] arr.each_cons(2) do |chunk| p chunk end # >> [1, 2] # >> [2, 3] # >> [3, 4] # >> [4, 5] # >> [5, 6] # >> [6, 7] # >> [7, 8] # >> [8, 9] 

Answer 4

如果你想实现自己的each_cons ：

 arr = [1, 2, 3, 4, 5, 6, 7, 8, 9] cons = 2 0.upto(arr.size - cons) do |i| p arr[i, cons] end 

输出：

 [1, 2] [2, 3] [3, 4] [4, 5] [5, 6] [6, 7] [7, 8] [8, 9]