如何动态更改path_to（）？

我目前有三种方法可以合并为一种：

def send_email(contact,email) end def make_call(contact, call) return link_to "Call", new_contact_call_path(:contact => contact, :call => call, :status => 'called') end def make_letter(contact, letter) return link_to "Letter", new_contact_letter_path(:contact => contact, :letter => letter, :status => 'mailed') end 

我想将三者合并为一个，这样我就可以将模型作为其中一个参数传递，它仍然可以正确地创建path_to。 我试图用以下方法做到这一点，但卡住了：

  def do_event(contact, call_or_email_or_letter) model_name = call_or_email_or_letter.class.name.tableize.singularize link_to "#{model_name.camelize}", new_contact_#{model_name}_path(contact, call_or_email_or_letter)" end 

感谢这里的答案，我尝试了以下内容，让我更接近：

 link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", :contact => contact, :status => "done", :model_name => model_name) ) 

但是我似乎无法弄清楚当它是一个：属性时如何通过＃{model_name}然后发送model_name的值，而不是作为字符串，而是引用该对象。

我得到了这个工作： – 给卡达达分，因为他让我朝着正确的方向:)

  def do_event(contact, call_or_email_or_letter) model_name = call_or_email_or_letter.class.name.tableize.singularize link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", :contact => contact, :status => 'done', :"#{model_name}" => call_or_email_or_letter ) ) end 

Answer 1

试试这个：

 def do_event(contact, call_or_email_or_letter) model_name = call_or_email_or_letter.class.name.tableize.singularize link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", contact, call_or_email_or_letter) ) end