尝试比较两个文本文件，并根据信息创建第三个文本文件

我有两个文本文件，master.txt和926.txt。 如果926.txt中有一行不在master.txt中，我想写一个新文件notinbook.txt。

我写了我能想到的最好的东西，但鉴于我是一个可怕的/新手程序员，它失败了。 这就是我所拥有的

g = File.new("notinbook.txt", "w") File.open("926.txt", "r") do |f| while (line = f.gets) x = line.chomp if File.open("master.txt","w") do |h| end while (line = h.gets) if line.chomp != x puts line end end end end end g.close 

当然，它失败了。 谢谢！

Answer 1

这应该工作：

 f1 = IO.readlines("926.txt").map(&:chomp) f2 = IO.readlines("master.txt").map(&:chomp) File.open("notinbook.txt","w"){ |f| f.write((f1-f2).join("\n")) } 

---

这是我的测试：

926.txt

 line1 line2 line3 line4 line5 

master.txt

 line1 line2 line4 

notinbook.txt

 line3 line5 

Answer 2

你可以这样做：

 master_lines = [] File.open("notinbook.txt","w") do |result| File.open("master.txt","r") do |master| master.each_line do |line| master_lines << line.chomp end end File.open("926.txt","r") do |query| query.each_line do |line| if !master_lines.include? line.chomp result.puts line.chomp end end end end 

Answer 3

使用： http ： //raa.ruby-lang.org/project/compare/

要么

％x（diff file1 file2）

要么

http://github.com/myobie/htmldiff/

Answer 4

希望这可以帮助

 dir = File.dirname(__FILE__) notinbook = "#{dir}/notinbook.txt" master = "#{dir}/master.txt" f926 = "#{dir}/926.txt" def file_into_ary(file) ary = [] File.open(file).each{ |line| ary << line } return ary end def write_difference(file, diff) File.open(file, 'w') do |file| diff.each do |line| file.write(line) end end end diff = file_into_ary(f926) - file_into_ary(master) write_difference(notinbook, diff) unless diff.empty?